0.28X^2+64x+0.3=0

Solution for 0.28X^2+64x+0.3=0 equation:

0.28X^2+64X+0.3=0

a = 0.28; b = 64; c = +0.3;
Δ = b2-4ac
Δ = 642-4·0.28·0.3
Δ = 4095.664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-\sqrt{4095.664}}{2*0.28}=\frac{-64-\sqrt{4095.664}}{0.56}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+\sqrt{4095.664}}{2*0.28}=\frac{-64+\sqrt{4095.664}}{0.56}
$